1 files changed, 0 insertions, 122 deletions
diff --git a/lib/edioutput/Interleaver.cpp b/lib/edioutput/Interleaver.cpp
deleted file mode 100644
index f26a50e..0000000
--- a/lib/edioutput/Interleaver.cpp
+++ /dev/null
@@ -1,122 +0,0 @@
-/*
-   Copyright (C) 2017
-   Matthias P. Braendli, matthias.braendli@mpb.li
-
-    http://www.opendigitalradio.org
-
-   EDI output,
-   Interleaving of PFT fragments to increase robustness against
-   burst packet loss.
-
-   This is possible because EDI has to assume that fragments may reach
-   the receiver out of order.
-
-   */
-/*
-   This file is part of ODR-DabMux.
-
-   ODR-DabMux is free software: you can redistribute it and/or modify
-   it under the terms of the GNU General Public License as
-   published by the Free Software Foundation, either version 3 of the
-   License, or (at your option) any later version.
-
-   ODR-DabMux is distributed in the hope that it will be useful,
-   but WITHOUT ANY WARRANTY; without even the implied warranty of
-   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
-   GNU General Public License for more details.
-
-   You should have received a copy of the GNU General Public License
-   along with ODR-DabMux.  If not, see <http://www.gnu.org/licenses/>.
-   */
-
-#include "Interleaver.h"
-#include <cassert>
-
-namespace edi {
-
-void Interleaver::SetLatency(size_t latency_frames)
-{
-    m_latency = latency_frames;
-}
-
-Interleaver::fragment_vec Interleaver::Interleave(fragment_vec &fragments)
-{
-    m_fragment_count = fragments.size();
-
-    // Create vectors containing Fcount*latency fragments in total
-    // and store them into the deque
-    if (m_buffer.empty()) {
-        m_buffer.emplace_back();
-    }
-
-    auto& last_buffer = m_buffer.back();
-
-    for (auto& fragment : fragments) {
-        const bool last_buffer_is_complete =
-                (last_buffer.size() >= m_fragment_count * m_latency);
-
-        if (last_buffer_is_complete) {
-            m_buffer.emplace_back();
-            last_buffer = m_buffer.back();
-        }
-
-        last_buffer.push_back(std::move(fragment));
-    }
-
-    fragments.clear();
-
-    while ( not m_buffer.empty() and
-            (m_buffer.front().size() >= m_fragment_count * m_latency)) {
-
-        auto& first_buffer = m_buffer.front();
-
-        assert(first_buffer.size() == m_fragment_count * m_latency);
-
-        /* Assume we have 5 fragments per AF frame, and latency of 3.
-         * This will give the following strides:
-         *    0        1     2
-         * +-------+-------+---+
-         * | 0   1 | 2   3 | 4 |
-         * |       |   +---+   |
-         * | 5   6 | 7 | 8   9 |
-         * |   +---+   |       |
-         * |10 |11  12 |13  14 |
-         * +---+-------+-------+
-         *
-         * ix will be 0, 5, 10, 1, 6 in the first loop
-         */
-
-        for (size_t i = 0; i < m_fragment_count; i++) {
-            const size_t ix = m_interleave_offset + m_fragment_count * m_stride;
-            m_interleaved_fragments.push_back(first_buffer.at(ix));
-
-            m_stride += 1;
-            if (m_stride >= m_latency) {
-                m_interleave_offset++;
-                m_stride = 0;
-            }
-        }
-
-        if (m_interleave_offset >= m_fragment_count) {
-            m_interleave_offset = 0;
-            m_stride = 0;
-            m_buffer.pop_front();
-        }
-    }
-
-    std::vector<PFTFragment> interleaved_frags;
-
-    const size_t n = std::min(m_fragment_count, m_interleaved_fragments.size());
-    std::move(m_interleaved_fragments.begin(),
-              m_interleaved_fragments.begin() + n,
-              std::back_inserter(interleaved_frags));
-    m_interleaved_fragments.erase(
-              m_interleaved_fragments.begin(),
-              m_interleaved_fragments.begin() + n);
-
-    return interleaved_frags;
-}
-
-}
-
-